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GATE 2023 CSE Question Paper PDF is available here. IIT Kanpur conducted GATE 2023 CSE exam on February 4, 2023 in the Forenoon Session from 09:30 AM to 12:30 PM. According to the initial reaction of the student, GATE CSE 2023 question paper was reported to be easy to moderate in difficulty. There were 34 MCQs, 15 MSQs and 16 NATs in GATE 2023 CSE Question Paper. 10 questions are from the General Aptitude section and 55 questions are from Engineering Mathematics and Core Discipline.
GATE 2023 CSE Question Paper PDF
| GATE 2023 | Question Paper with Solution PDF |
|---|---|
| GATE 2023 CSE Question Paper | Download PDF |
Question Paper Source: GATE Academy and BYJUs
GATE 2023 CSE Question Paper Analysis
| Details | Paper Analysis Highlights |
|---|---|
| Overall Difficulty | Easy to Moderate |
| Number of MCQs | 34 |
| Number of MSQs | 15 |
| Number of NATs | 16 |
Also Check:
GATE Previous Year Question Papers
Other PG Exam Question Papers
GATE Questions
1. The area of a rhombus whose vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order, is:
The area of a rhombus whose vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order, is:
12 sq.units
24 sq.units
2. Franz looked for opportunities to skip school to do what?
Franz looked for opportunities to skip school to do what?
water the plants
collect birds eggs
4. The points (-1, –2), (1, 0), (-1, 2), (-3, 0) form a quadrilateral of type:
- Square
- Rectangle
5. In p-type semiconductor density of mobile holes exceeds that of conduction electrons. Hence, minority carriers in p -type semiconductor are conduction (free) electrons.
In p-type semiconductor density of mobile holes exceeds that of conduction electrons. Hence, minority carriers in p -type semiconductor are conduction (free) electrons.
a
b
6. Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)
Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)
- N2 + O2 → N2O5 (unbalanced equation)
- 2N2 + 5O2 → 2N2O5
- option 3
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