GATE 2018 Production and Industrial Engineering (PI) Question Papers with Answer Key PDFs- (February 03)

GATE 2018 PI (Production and Industrial Engineering) Question Paper with Answer Key PDFs is available for download. GATE 2018 PI was conducted on 3rd February 2018 in the afternoon session by IIT Guwahati. GATE 2018 PI Question Paper included 34 MCQs (Multiple Choice Questions) and 31 NATs (Numerical Answer Type).

GATE 2018 PI (Production and Industrial Engineering) Question Papers with Answer Key PDFs- (February 03)

GATE 2018 Production and Industrial Engineering (PI) Question Paper PDF GATE 2018 Production and Industrial Engineering (PI) Answer Key PDF
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GATE 2018 PI: Weightage of Questions

GATE 2018 PI question paper carried a total of 65 questions. The topics covered were General Aptitude and Production and Industrial Engineering. There were 10 MCQs from General Aptitude carrying one march each. The topic PI has a total of 55 questions. Out of the 55 questions 25 questions carried 1 mark and the other 25 questions carried 2 marks.

GATE Previous Year Question Papers

Aspirants preparing for GATE upcoming exams should practice the previous year Question papers to score well. Candidates must solve all the questions of previous years' GATE EC papers in order to evaluate their preparation and performance.

Other PG Exam Question Papers:

GATE Questions

  • 1.

    Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)

      • N2 + O2 → N2O5 (unbalanced equation)
      • 2N2 + 5O2 → 2N2O5
      • option 3

    • 2.
      Question Text

        • A
        • B

      • 3.

        Franz looked for opportunities to skip school to do what?

          • water the plants

          • collect birds eggs


        • 4.

          \((1+i)^{2}\div i(2i-1)\)

            • a

            • b


          • 5.

            The area of a rhombus whose vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order, is:

              • 12 sq.units

              • 24 sq.units


            • 6.
              For the reaction, $H_{2} + I_{2} {\rightleftharpoons} 2HI, K= 47.6.$ If the initial number of moles of each reactant and product is 1 mole then at equilibrium

                • $\left[I_{2}\right]=\left[H_{2}\right], \left[I_{2}\right] > \left[HI\right]$
                • $({\frac{x^3}{9}})$
                • \(\left[I_{2}\right]>\left[H_{2}\right], \left[I_{2}\right] = \left[HI\right]\)

                • $\omega\propto\,n^{\frac{1}{3}}$

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