GATE 2018 EY Question Papers with Answer Key PDFs (February 3- Forenoon Session)

GATE 2018 EY Question Paper with Answer Key PDF for the exam conducted on the 3rd of February, 2018 in the forenoon session is available for download. The exam was held by IIT Guwahati. GATE 2018 EY Question Paper was classified as lengthy with questions ranging from moderate to tough.

GATE 2018 EY Question Papers with Answer Key PDFs (February 3 - Forenoon Session)

GATE 2018 EY Question Paper	GATE 2018 EY Question Paper
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GATE 2018 EY Answer Key Details

Question No.	Section	Answer	Question No.	Section	Answer
1	GA	A	24	EY	0.179 to 0.181
2	GA	C	25	EY	0.99 to 1.01
3	GA	B	26	EY	A
4	GA	B	27	EY	C
5	GA	B	28	EY	C
6	GA	A	29	EY	D
7	GA	D	30	EY	B
8	GA	D	31	EY	D
9	GA	B	32	EY	B
10	GA	C	33	EY	D
1	EY	B	34	EY	A
2	EY	D	35	EY	A
3	EY	B	36	EY	C
4	EY	B	37	EY	C
5	EY	A	38	EY	A
6	EY	B	39	EY	A
7	EY	C	40	EY	C
8	EY	B	41	EY	A (or) D
9	EY	B	42	EY	D
10	EY	C	43	EY	D
11	EY	D	44	EY	A
12	EY	D	45	EY	C
13	EY	C	46	EY	C
14	EY	D	47	EY	B
15	EY	D	48	EY	B
16	EY	A	49	EY	D
17	EY	D	50	EY	5.9 to 6.1
18	EY	B	51	EY	0.09 to 0.11
19	EY	C	52	EY	0.99 to 1.01
20	EY	A	53	EY	0.0019 to 0.0021
21	EY	D	54	EY	0.49 to 0.51
22	EY	A	55	EY	0.299 to 0.301
23	EY	99 to 101

GATE 2018 EY PAPER ANALYSIS

GATE 2018 EY Question Paper included 65 questions divided into General Aptitude and Core Discipline with a weightage of 15 and 85 marks respectively. The number of 1 mark and 2 marks questions have been listed in the table below for referenc

Type of Questions	General Aptitude		Core Discipline
Type of Questions	Number of Questions	Marks	Number of Questions	Marks
No. of 1 mark MCQs	5	5	22	22
No. of 2 marks MCQs	5	10	3	6
No. of 1 mark NATs	0	0	24	48
No. of 2 marks NATs	0	0	6	12

GATE Previous Year Question Papers:

Solving previous year's GATE Engineering Sciences Papers is important since it gives you an idea of how the GATE sets the paper. GATE Previous Year Papers can help you comprehend the changes that have occurred in this test in the past.

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1.
\((1+i)^{2}\div i(2i-1)\)

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2.
Write a balanced equation for the reaction of molecular nitrogen (N₂) and oxygen (O₂) to form dinitrogen pentoxide. \((f(x)=x^2)\)

N₂ + O₂ → N₂O₅ (unbalanced equation)
2N₂ + 5O₂ → 2N₂O₅
option 3

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3.
sample text 2

dsfdg
fdgd

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4.
sample text

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5.
M. Hamel is introduced as a ruler-wielding teacher. This demonstrates that:

he is adamant.
he is a hard taskmaster.

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6.
In p-type semiconductor density of mobile holes exceeds that of conduction electrons. Hence, minority carriers in p -type semiconductor are conduction (free) electrons.

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GATE 2018 EY Question Papers with Answer Key PDFs (February 3- Forenoon Session)