GATE 2013 Computer Science and Information Technology (CS) Slot 4 Question Paper with Answer Key PDFs (Offline) (February 10- Forenoon Session)

GATE 2013 Computer Science and Information Technology (CS) Slot 4 Question Papers with Answer Key PDFs is now available for download. GATE 2013 Cs Paper was conducted by IIT Bombay in four sessions. According to the students, the difficulty level of the paper of session 4 ranged from Easy to Moderate as compared to other sessions. There were a total of 65 objective-type questions of 100 Marks.

GATE 2013 Computer Science and Information Technology (CS) Slot 4 Question Paper with Answer Key PDFs (February 10)

GATE 2013 Computer Science and Information Technology (CS) Question Paper GATE 2013 Computer Science and Information Technology (CS) Answer Key
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GATE 2013 Computer Science and Information Technology (CS) Slot 4 Question Paper Analysis

GATE 2013 CS Slot 4 question paper was fully based on MCQs carrying 100 Marks.10 questions out of 100 we’re of general aptitude carrying 15 Marks.

The table below shows the frequency of MCQs carrying 1 and 2 marks asked in GATE 2013 EY paper-

Type of Questions General Aptitude Core Discipline
Number of Questions Marks Number of Questions Marks
No. of 1 mark MCQs 5 5 25 25
No. of 2 marks MCQs 5 10 30 60

GATE Previous Year Question Paper

Aspirants preparing for GATE upcoming exams should practice the previous year Question papers to score well. Candidates must solve all the questions of previous years' GATE CS papers in order to evaluate their preparation and performance.

Other PG Exam Question Papers:

GATE Questions

  • 1.

    In p-type semiconductor density of mobile holes exceeds that of conduction electrons. Hence, minority carriers in p -type semiconductor are conduction (free) electrons.


     

      • a

      • b


    • 2.

      sample text

        • dfb

        • dfg


      • 3.

        Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)

          • N2 + O2 → N2O5 (unbalanced equation)
          • 2N2 + 5O2 → 2N2O5
          • option 3

        • 4.

          M. Hamel is introduced as a ruler-wielding teacher. This demonstrates that:

            • he is adamant.

            • he is a hard taskmaster.


          • 5.
            For the reaction, $H_{2} + I_{2} {\rightleftharpoons} 2HI, K= 47.6.$ If the initial number of moles of each reactant and product is 1 mole then at equilibrium

              • $\left[I_{2}\right]=\left[H_{2}\right], \left[I_{2}\right] > \left[HI\right]$
              • $({\frac{x^3}{9}})$
              • \(\left[I_{2}\right]>\left[H_{2}\right], \left[I_{2}\right] = \left[HI\right]\)

              • $\omega\propto\,n^{\frac{1}{3}}$

            • 6.
              Direction: In these tests you will find an Incomplete Figure and four Answer Figures. You have to select one diagram from the Answer Figures which fits into the blank column in Incomplete Figure in order to complete it
              Incomplete Figure

              Answer Figures

                • Figure (a)

                • Figure (b)

                • Figure ©

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