GATE 2012 Chemistry (CY) Question Paper with Answer Key PDFs (Offline) (February 12

GATE 2012 Chemistry (CY) Question Paper with Answer Key PDFs are available for download. The exam was organized by IIT Delhi on February 12, 2012, in offline mode. GATE 2012 CY Paper consisted of 85% of the core subject, and the rest of 15% was taken by the general aptitude section. Candidates can now download the question paper along with its answer key from the links below provided.

GATE 2012 Chemistry (CY) Question Paper with Answer Key PDFs (Offline) (February 12 – Forenoon Session)

GATE 2012 CY Question Paper	GATE 2012 CY Answer Key
Download PDF	Download PDF

GATE 2012 CY Answer Key Details

Question No.	Answer	Question No.	Answer
1	B	34	Marks to All
2	C	35	A
3	C	36	B
4	D	37	D
5	B	38	A
6	C	39	Marks to All
7	D	40	D
8	C	41	A
9	D	42	A
10	C	43	D
11	C	44	B
12	D	45	B
13	C	46	C
14	D	47	Marks to All
15	D	48	B
16	D	49	D
17	D	50	B
18	C	51	D
19	B	52	A
20	C	53	B
21	A	54	A
22	B	55	A
23	B	56	D
24	D	57	B
25	B	58	B
26	D	59	D
27	B	60	A
28	C	61	A
29	C	62	C
30	A	63	D
31	A	64	A
32	C	65	A
33	A

GATE 2012 CY Question Paper Analysis

GATE 2012 CY question paper consisted of 65 questions on whole. The division of marks was 1 mark and 2 marks. There were two pairs of questions of common data questions and 2 pairs of linked answer questions.

The below table is a brief description of the divisions of questions in GATE CY 2012.

Type of Questions	General Aptitude		Core Discipline
Type of Questions	Number of Questions	Marks	Number of Questions	Marks
No. of 1 mark MCQs	5	5	25	25
No. of 2 marks MCQs	5	10	30	60

GATE Previous Year Question Paper

Going through GATE previous year question paper helps in getting strong hold for the important topics from the syllabus. Candidates can download Previous Year Questions for preparation and practice of GATE CY paper.

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1.
The area of a rhombus whose vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order, is:

12 sq.units
24 sq.units

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2.
For the reaction, $H_{2} + I_{2} {\rightleftharpoons} 2HI, K= 47.6.$ If the initial number of moles of each reactant and product is 1 mole then at equilibrium

$\left[I_{2}\right]=\left[H_{2}\right], \left[I_{2}\right] > \left[HI\right]$
$({\frac{x^3}{9}})$
$\left[I_{2}\right]>\left[H_{2}\right], \left[I_{2}\right] = \left[HI\right]$
$\omega\propto\,n^{\frac{1}{3}}$

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3.
M. Hamel is introduced as a ruler-wielding teacher. This demonstrates that:

he is adamant.
he is a hard taskmaster.

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4.
Question Text

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5.
Direction: In these tests you will find an Incomplete Figure and four Answer Figures. You have to select one diagram from the Answer Figures which fits into the blank column in Incomplete Figure in order to complete it
Incomplete Figure

Answer Figures

Figure (a)
Figure (b)
Figure ©

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6.
In p-type semiconductor density of mobile holes exceeds that of conduction electrons. Hence, minority carriers in p -type semiconductor are conduction (free) electrons.

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Fees Structure

Structure based on different categories

Categories	State
General	1400
Women	900
sc	900
pwd	900

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GATE 2012 Chemistry (CY) Question Paper with Answer Key PDFs (Offline) (February 12– Forenoon Session)