GATE 2012 Computer Science and Information Technology (CS) Question Paper with Answer Key PDFs (Offline) (February 12- Forenoon Session)

GATE 2012 Computer Science and Information Technology (CS) Question Paper with Answer Key PDFs are available for download. GATE 2012 was held on February 12, 2012 in the offline medium. It was conducted by IIT Delhi. The difficulty of the paper was similar to the previous year. The paper seemed to have topics evenly distributed. In GATE 2012 CS Paper, 85% of the questions were from the core subject and the rest from the general aptitude section.

GATE 2012 Computer Science and Information Technology (CS) Question Paper with Answer Key PDFs (Offline) (February 12 – Forenoon Session)

GATE 2012 CS Question Paper	GATE 2012 CS Answer Key
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GATE 2012 CS Question Paper Analysis

GATE 2012 CS paper had 65 questions in total with a division of a core subject, engineering mathematics, and general aptitude. The marking scheme of the paper ranged from 1 mark questions to 2 marks questions. The maximum questions in the paper were from Databases followed by Algorithms, Computer Networks, Operating systems and Programming, and Data structures. The General Aptitude section contained questions on numerical ability and verbal ability.

Type of Questions	General Aptitude		Core Discipline
Type of Questions	Number of Questions	Marks	Number of Questions	Marks
No. of 1 mark MCQs	5	5	25	25
No. of 2 marks MCQs	5	10	30	60

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1.
For the reaction, $H_{2} + I_{2} {\rightleftharpoons} 2HI, K= 47.6.$ If the initial number of moles of each reactant and product is 1 mole then at equilibrium

$\left[I_{2}\right]=\left[H_{2}\right], \left[I_{2}\right] > \left[HI\right]$
$({\frac{x^3}{9}})$
$\left[I_{2}\right]>\left[H_{2}\right], \left[I_{2}\right] = \left[HI\right]$
$\omega\propto\,n^{\frac{1}{3}}$

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2.
The area of a rhombus whose vertices are (3, 0), (4, 5), (-1, 4) and (-2,-1) taken in order, is:

12 sq.units
24 sq.units

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3.
sample text 2

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4.
sample text

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5.
In p-type semiconductor density of mobile holes exceeds that of conduction electrons. Hence, minority carriers in p -type semiconductor are conduction (free) electrons.

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6.
Write a balanced equation for the reaction of molecular nitrogen (N₂) and oxygen (O₂) to form dinitrogen pentoxide. $(f(x)=x^2)$

N₂ + O₂ → N₂O₅ (unbalanced equation)
2N₂ + 5O₂ → 2N₂O₅
option 3

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GATE 2012 Computer Science and Information Technology (CS) Question Paper with Answer Key PDFs (Offline) (February 12- Forenoon Session)