GATE 2010 Engineering Sciences (XE) Question Paper with Answer Key PDFs (February 14 - Forenoon Session)

GATE 2010 XE Question Paper with Answer Key PDFs are available now. The exam was conducted in offline mode on February 14, 2010 in the Forenoon Session. IIT Guwahati conducted the paper. The difficulty level of the paper was rated moderate. There are a total of 65 questions carrying 100 marks. Out of which 10 questions were asked from general aptitude and 55 questions were asked from core discipline.

GATE 2010 Engineering Sciences (XE) Question Paper with Answer Key PDFs (February 14 - Forenoon Session)

GATE 2010 XE Question Paper GATE 2010 XE Answer Key
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GATE 2010 XE Paper Analysis

Questions 1 to 25 carry 1 mark each and Questions 26 to 55 carry 2 marks each of GATE 2010 XE Question Paper. Questions 56 to 65 belong to the General Aptitude Section. Question 48-51 (2 pairs) are Common Data Questions and Question Pairs (Q. 52, 53) and (Q. 54, 55) are linked answer questions.

Type of Questions General Aptitude Core Discipline
Number of Question Marks Number of Questions Marks
No. of 1 mark MCQs 5 5 25 25
No. of 2 marks MCQs 5 10 30 60
No. of 2 marks Common data Questions - - 2 4
No. of 2 marks Linked Answer Questions - - 2 4

GATE Previous year Question Paper

Students should practice 1 question paper daily before appearing for the actual examination to check the level of their preparation. This will help them understand the demand of the examination in a better way. Find below the previous years’ question papers of GATE:

Other PG Exam Question Papers:

GATE Questions

  • 1.

    \((1+i)^{2}\div i(2i-1)\)

      • a

      • b


    • 2.

      new

        • new one

        • new one two


      • 3.
        The points (-1, –2), (1, 0), (-1, 2), (-3, 0) form a quadrilateral of type:

          • Square
          • Rectangle

        • 4.

          Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)

            • N2 + O2 → N2O5 (unbalanced equation)
            • 2N2 + 5O2 → 2N2O5
            • option 3

          • 5.

            M. Hamel is introduced as a ruler-wielding teacher. This demonstrates that:

              • he is adamant.

              • he is a hard taskmaster.


            • 6.
              For the reaction, $H_{2} + I_{2} {\rightleftharpoons} 2HI, K= 47.6.$ If the initial number of moles of each reactant and product is 1 mole then at equilibrium

                • $\left[I_{2}\right]=\left[H_{2}\right], \left[I_{2}\right] > \left[HI\right]$
                • $({\frac{x^3}{9}})$
                • \(\left[I_{2}\right]>\left[H_{2}\right], \left[I_{2}\right] = \left[HI\right]\)

                • $\omega\propto\,n^{\frac{1}{3}}$

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