GATE 2010 CE Question Paper with Answer Key PDFs - February 14, 2010 (Forenoon Session)

GATE 2010 CE Question Paper with Answer Key PDF is now available for free download. The exam was conducted by the Indian Institute of Technology (IIT) Guwahati in an offline mode on February 14, 2010, in the forenoon session. GATE 2010 CE question paper had 65 questions out of which the initial 55 questions were from the core subject of civil engineering and the latter 10 questions were from the section of General Aptitude. All the questions were for either 1 mark or 2 marks, collectively making the paper worth a total of 100 marks. All the questions were found in the format of Multiple Choices Questions (MCQs) only.

GATE 2010 CE Question Paper with Answer Key PDFs - February 14, 2010 (Forenoon Session)

GATE 2010 CE Question Paper GATE 2010 CE Answer Key
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GATE 2010 CE Paper Analysis

According to the students, the difficulty level of the exam was equally distributed between various questions. They found certain MCQs as easy whereas certain questions, especially from the General Aptitude section were reported to be difficult.

Type of Questions General Aptitude Core Discipline
Number of Questions Marks Number of Questions Marks
No. of 1 marks MCQs 5 5 25 25
No. of 2 marks MCQs 5 10 30 60
No. of 1 marks NATs - - - -
No. of 2 marks NATs - - - -

GATE Previous Year Question Papers

All the previous year GATE question papers are available in the links given below. Solving these GATE previous year papers shall help the candidates in analyzing the exam pattern and understanding the question format. Going through these past year question papers is a must to ensure a concrete preparation for GATE exam.

Other PG Exam Question Papers:

GATE Questions

  • 1.

    In p-type semiconductor density of mobile holes exceeds that of conduction electrons. Hence, minority carriers in p -type semiconductor are conduction (free) electrons.


     

      • a

      • b


    • 2.

      new

        • new one

        • new one two


      • 3.
        The points (-1, –2), (1, 0), (-1, 2), (-3, 0) form a quadrilateral of type:

          • Square
          • Rectangle

        • 4.
          For the reaction, $H_{2} + I_{2} {\rightleftharpoons} 2HI, K= 47.6.$ If the initial number of moles of each reactant and product is 1 mole then at equilibrium

            • $\left[I_{2}\right]=\left[H_{2}\right], \left[I_{2}\right] > \left[HI\right]$
            • $({\frac{x^3}{9}})$
            • \(\left[I_{2}\right]>\left[H_{2}\right], \left[I_{2}\right] = \left[HI\right]\)

            • $\omega\propto\,n^{\frac{1}{3}}$

          • 5.
            Question Text

              • A
              • B

            • 6.

              sample text 2

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                • fdgd

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