0.2 moles of an ideal gas is taken round the cycle ABC as shown in the figure. The path B → C is an adiabatic process, A → B is an isochoric process and C → A is an isobaric process. The temerature at A and B are T = 300 K and T = 500 K and pressure at A is 1 atm and volume at A is 4.9 L. The volume at C is
(Given : $\gamma=\frac{Cp}{C_{V}}=\frac{5}{3}, R = 8.205 × 10^{-2}$ L atm mol$^{-1}$
$K^{-1}, \left(\frac{3}{2}\right)^{^{2/5}} =0.81$