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Question:
Work done in turning a magnet of magnetic moment M by an angle of 90º from the mgnetic meridian is n times the corresponding work done to turn through an angle of 60º, where n is
Updated On: Apr 5, 2022
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The Correct Option is B
Solution and Explanation
W = - MB (cos 90º - cos 0º) = MB
W = - MB (cos 60º - cos 0º)
= -MB$\left(\frac{1}{2}-1\right)=\frac{1}{2}$ MB
Which is $=\frac{1}{2}$ W
As, W = n W $\quad\quad$ ∴ n = 2
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