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Question:
If same charge 'q' is placed inside a sphere and cube, having radius 1 m and side 2 m respectively. What will be the ratio of flux passing through them:
Updated On: Apr 5, 2022
- 1 : 1
- 1 : 8
- 8 : 1
- 1 : 2
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The Correct Option is A
Solution and Explanation
The total flux linked with a closed surface is $\frac{1}{\varepsilon_{0}}$ times the charge enclosed by the closed surface.
enclosed Flux, $\phi = \frac{q_{enclosed}}{\varepsilon_{0}}$
Since enclosed charge is same, so the flux will be same.
flux through sphere = flux through cube $\Rightarrow$ 1 : 1
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