For admission in PEC, you at least need to have 75% in your intermediate exams and cleared the JEE Main cut-off for the institute.
The following table shows the JEE Main Round 1 cut-offs for PEC in 2020:
Category
|
Sub-Category
|
B.Tech CSE
|
B.Tech ECE
|
General
|
OS*
|
199-6404
|
6871-13169
|
HS*
|
1438-10654
|
11011-19152
|
SC
|
OS
|
990-2483
|
3454-4530
|
HS
|
1531-3345
|
4015-8676
|
ST
|
OS
|
879-1256
|
1457-2545
|
General PwD
|
OS
|
143-153
|
1164-1164
|
HS
|
196-258
|
539-939
|
*Here, 'other state' is OS, and 'home state' is HS.
Seeing the cut-off rank, you might not get PEC Chandigarh at your mentioned profile.
- With 92.8% in 10+2, you have cleared one basic eligibility for the institute.
- Another eligibility is clearing JEE Mains cut-off for PEC. At the mentioned score of 116 in JEE Main, your rank will be approximately around 55000. This rank cannot get a seat in any of the 6 rounds.
If you are desperate to join this year, then you can search for CSE/ECE branch other institutes, as per your JEE rank. But, if you can have time in your hands, you can give another attempt in JEE Mains.
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