The Present Age Of A Father Is 3 Years More Than Three Times The Age Of His Son

‘The Present Age Of A Father Is 3 Years More Than Three Times The Age Of His Son’ is a GMAT Maths problem that can be solved in two ways. First by following the basic arithmetic rules and by using the basic algebraic equations. In this article, we have covered both the solution types along with explanations.

GMAT quantitative section examines the analyzing and reasoning ability of the GMAT test-takers. The topic ‘The Present Age Of A Father Is 3 Years More Than Three Times The Age Of His Son’ is having 5 optional choices. Candidates need to choose the correct answer. GMAT Quantitative Reasoning has mainly the two divisions-

GMAT Data Sufficiency: The GMAT Data Sufficiency topics include number properties, algebra, geometry, arithmetic, and many more.
GMAT Problem Solving: In the problem-solving section, the basic maths concepts are being measured. Topics like integers, inequalities, number systems, fractions, and more are covered in this section.

Topic: The present age of a father is 3 years more than three times the age of his son. Three years hence , father's age will be 10 years more than twice the age of the son. Present age of the father is..

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Answer: D

Model Answer 1

This problem statement has only one approach to solve.

Explanation:

There is only a single approach to solve this sum. Thus, a single approach has been depicted in the proceeding model answer.
The above-mentioned equation can be solved with an approach of one variable.
Let us consider the present age of the son to be x.
Therefore, the present age of the father will be represented by the equation: 3x + 3
Thus, in three years, son’s age will be x+3 and fathers age will be 3x + 3 + 3.
However, it is mentioned in the question that the father's age will be 10 years more than twice the age of the son. Thus, the equation that can be derived from this mentioned situation is;
(3x + 3 + 3) = 2(x + 3) + 10
Solving the equation we get: 3x + 6 = 2x + 16
Subtract 2x from both sides: x + 6 = 16
Subtract 6 from both sides: x = 10
Thus, replacing the values of x in the first formed equations will yield the present age of the father and son. The age of the son is 10.
Since 3x + 3 = the present age of the father, the father's present age = 3(10) + 3 = 33

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The Present Age Of A Father Is 3 Years More Than Three Times The Age Of His Son

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