Question: Solve for x: |3x-2|≤ ½
- (½ , ⅚)
- (3/2 , 6/5)
- (5/2, ¾)
- (3/7 , 4/9)
- (6/7 , 4/3)
Correct Answer: A
Solution and Explanation:
Approach Solution 1:
The problem statement asks to solve the equation |3x-2|≤ ½ for x. There are two cases that can be considered for the same.
To get the appropriate answer, the following are the two cases that have been assessed to get the correct answer.
The first case has been evaluated as followed:
The first case states that whatever is inside the modulus is >= 0
⇒3x-2 ≥ 0 => 3x ≥ 2 => x ≥ ⅔ ~ 0.67
⇒|3x-2| = 3x-2 [with (as |X| = X when X >= 0)]
⇒ 3x-2 ≤ ½
⇒3x ≤ 2 + ½
⇒3x ≤ \(\frac{4+1}{2}\)
⇒ x ≤ \(\frac{5}{2*3}\)
⇒x ≤ 5/6
However, the given condition was that x \(\geq\) 2/3.
Depending on this condition and the value of x determined from the above equation in case 1, it can be stated that-
\(\frac{2}{3}\leq x \leq \frac{5}{6}\)
It is clear from the above equation that the value for x is ⅔ and ⅚
However, another case that can be used to find the value for the x is as follows:
The second case states that whatever is inside the modulum < 0
This can be further explained using the following equation and solving it-
⇒3x-2 < 0 => 3x < 2 => x < \(\frac{2}{3}\)
⇒|3x-2| = -(3x-2) [ where |x| = -x and x < 0
⇒-(3x-2) ≤ \(\frac{1}{2}\)
⇒-3x + 2 ≤ \(\frac{1}{2}\)
⇒-3x ≤ \(\frac{1}{2}\) - 2
⇒-3x ≤ \(\frac{1-4}{2}\)
⇒-3x ≤ \(\frac{-3}{2}\)
⇒x ≥ \(\frac{-3}{2x-3}\) ( multiplying both the sides with -3 will help in reversing the sign of inequality because of which this situation has been considered)
⇒x ≥ 2
But the given condition stated that x <\(\frac{2}{3}\) and x is not < \(\frac{2}{3}\)
Thus, in this case, no solution could be evaluated thereby stating that this case cannot be considered viable for solving the equation.
Thus, considering both cases, it can be stated that Option A is the correct answer implying that the value of x is ⅔ and ⅚ which satisfies the first condition.
Approach Solution 2:
The problem statement asks to solve the equation |3x-2|≤ ½ for x.
Another approach to be considered for this problem is in the terms of both positive and negative evaluations.
This implies the following method to be employed-
To derive the value of x, the opening of the mode with a positive sign would imply-
⇒3x-2 ≤ 1/2
⇒x ≤ 5/6
This can be considered to be the value for x which is incorporated in one of the cases.
Another case can be derived with the negative sign for opening the mode. This would imply-
⇒-3x + 2 ≤ ½
⇒1/2 ≤ x
Hence, from both cases, the value of x is derived as ½ and ⅚.
Approach Solution 3:
The problem statement asks to solve the equation |3x-2|≤ ½ for x.
∣3x−2∣ ≤ 1/2
3x−2 ≤1/2
or 3x−2 ≥ −1/2
Again, 3x−2 ≤ 1/2
6x−4 ≤ 1
6x ≤ 5
x ≤ 5/6
x ≤ 5/6 or x ≥ 1/2
Therefore, 1/2 ≤ x ≤ 5/6
Hence, the value of x is derived as ½ and ⅚
“Solve for x: |3x-2|≤ ½”- is a topic of the GMAT Quantitative reasoning section of the GMAT exam. GMAT Problem Solving questions are designed to test the calculative skills and intellectual level of the candidates to solve quantitative problems. GMAT Quant practice papers offer various types of questions that enable the candidates to strengthen their mathematical knowledge.
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