
bySayantani Barman Experta en el extranjero
Question: If the average of four distinct positive integers is 60, how many integers of these four are less than 50?
- The median of the three largest integers is 51 and the sum of two largest integers is 190.
- The median of the four integers is 50.
- Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
- Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
- BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
- EACH statement ALONE is sufficient.
- Statements (1) and (2) TOGETHER are NOT sufficient.
“If the average of four distinct positive integers is 60, how many integers of these four are less than 50?”– is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken f0rom the book "GMAT Quantitative Review". GMAT Quant section consists of a total of 31 questions. GMAT Data Sufficiency questions consist of a problem statement followed by two factual statements. GMAT data sufficiency comprises 15 questions which are two-fifths of the total 31 GMAT quant questions.
Answer
Approach Solution 1:
There is only one approach solution to this problem.
It’s almost always better to express the average in terms of the sum: the average of four distinct positive integers is 60, means that the sum of four distinct positive integers is 4 * 60 = 240
Say four integers are a, b, c and d so that 0 < a < b < c < d.
So, we have that a + b + c + d = 240
(1) The median of the three largest integers is 51 and the sum of two largest integers is 190
The median of {b,c,d} is 51 means that c = 51. Now, if b = 50, then only a, will be less than 50, but if b < 50, then both a and b, will be less than 50.
But we are also given that c + d = 190.
Substitute this value in the above equation: a + b + 190 = 240, which boils down to a + b = 50
Now, given that all integers are positive then both a and b must be less than 50.
Hence this statement is sufficient.
(2) The median of the four integers is 50. The median of a set with even number of terms is the average of two middle terms, so median = \(\frac{b+c}{2}\)= 50
Since b < c then b < 50 < c, so both a and b are less than 50.
Hence this statement is sufficient.
Correct Answer: D
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