
bySayantani Barman Experta en el extranjero
Question: If ax + b = 0, is x > 0?
- a + b > 0
- a – b > 0
- Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient.
- Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient.
- BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
- EACH statement ALONE is sufficient.
- Statements (1) and (2) TOGETHER are NOT sufficient.
“If ax + b = 0, is x > 0?”– is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book "GMAT Quantitative Review". GMAT Quant section consists of a total of 31 questions. GMAT Data Sufficiency questions consist of a problem statement followed by two factual statements. GMAT data sufficiency comprises 15 questions which are two-fifths of the total 31 GMAT quant questions.
Answer:
Approach Solution 1:
Given: b = -ax
Question: is x > o
(1) a + b > 0 ----- a – ax > 0 ----- a(1 – x) > 0 ----- either a > 0 and 1 – x > 0, so x < 1 OR a < 0 and 1 – x < 0, so x > 1
NOT SUFFICIENT.
(2) a – b > 0 ---- a + ax > 0 ----- a(1 + x) > 0 ---- either a > 0 and 1 + x > 0, so x > -1 OR a < 0 and 1 + x < 0, so x < -1
NOT SUFFICIENT
(1) + (2) Sum (1) and (2) (we can do this as the signs of these inequalities are in the same direction)
(a + b) + (a – b) > 0 ---- a > 0, so we have the first range from (!): x < 1 and first case from (2): x > -1 ---- -1 < x < 1 so x may or may not be negative.
NOT SUFFICIENT
Correct option: E
Approach Solution 2:
You can look at this geometrically – because the equation is that of a line, the question is set up so that you can look at it as co-ordinate geometry question. The equation y = ax + b is the equation of a line with the slope a and y-intercept b. when we plug in y = 0, we are finding the x-intercept of the line. So the question is just asking if the x-intercept of the line is positive. In a diagram that would be true if our line crosses the x-axis to the right of the origin (0,0).
Now, using both the statements, if a > -b and a > b, then a > |b|. so a is clearly positive, and our line has a positive slope and is climbing as you move to the right. We can now just draw two different scenarios on the coordinate plane, one where b is positive and one where b is negative. If you choose, say, b = 1 and a = 5, then if you quickly sketch your line you’ll see that the x-intercept of y = ax + b is negative, and if b = -1 and a = 5 then if you quickly sketch your line you’ll see that the x-intercept of y = ax +b is positive, so NOT SUFFICIENT.
Correct option: E
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