Question: Given k is a nonzero integer, is k>0?
(1) |k−4|=|k| + 4
(2) k>k^3
- Statement (1) ALONE is sufficient but statement (2) ALONE is not sufficient.
- Statement (2) ALONE is sufficient but statement (1) ALONE is not sufficient.
- BOTH statements TOGETHER are sufficient, but NEITHER statement ALONE is sufficient.
- EACH statement ALONE is sufficient.
- Statements (1) and (2) TOGETHER are not sufficient.
“Given k is a nonzero integer, is k>0?”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book "GMAT Quantitative Review". GMAT Quant section consists of a total of 31 questions. GMAT Data Sufficiency questions consist of a problem statement followed by two factual statements. GMAT data sufficiencycomprises 15 questions which are two-fifths of the total 31 GMAT quant questions.
Solution and Explanation:
Approach Solution 1:
Given to us that k is a non-zero integer. It is asked if k > 0 or not.
There are two statements, we have to check whether these two statements are sufficient to answer the problem or not.
Coming to the first statement,
1)|k-4| = |k| + 4
In order to remove the mod we have to break the values of k into different regions.
We’ll break the values of k where the mod values become 0.
|k-4| = 0
k = 4
also,
|k| = 0
k = 0
Therefore we’ll break the values into three different regions
K <= 0 , 0 < k < 4 and k >= 4
So for k <= 0
Given equation becomes,
| k-4 | = | k| + 4
-(k-4) = - k + 4
- k + 4 = -k + 4
As we get 0 = 0 the value of k cannot be found but the equation is satisfied.
Therefore k < 0
for the second case,
0 < k < 4
| k-4 | = | k| + 4
-(k-4) = k + 4
-k+4 = k + 4
2k = 0
k=0
But we assumed k > 0
Therefore k cannot be in the region 0 < k< 4
For case 3,
K >= 4
| k-4 | = | k| + 4
k-4 = k+ 4
We get 8 = 0
Therefore k cannot be greater than 4.
Finally, we get k <0. Therefore this statement is sufficient to get the answer.
Coming to the second statement,
K > k^3
On the number line, it should be noted that the value of x > x^3 only when x < -1 or 0 < x < 1
But in the given question, it is given that k is an integer. Therefore it will not lie in the region 0 < x < 1 Therefore k must be less than -1.
We can say that k < 0 . Therefore this statement is sufficient to answer the question.
Correct Answer: D
Approach Solution 2:
Assumed to be a non-zero integer, k. If k > 0 or not is the question.
There are two assertions, and we must determine if they are adequate to address the issue.
When it comes to the first claim,
1)|k-4| = |k| + 4
We must divide the values of k into several areas in order to eliminate the mod.
Where the mod values become 0, we will divide the values of k.
k = 4 and |k-4| = 0.
|k| = 0\sk = 0
As a result, we'll divide the data into three zones.
K = 0, K >= 4, and K = 0
Thus, if k = 0,
As a result of the above equation, | k-4 | = | k| + 4 -(k-4) = - k + 4 - k + 4 = -k + 4
The value of k cannot be obtained since we arrive to 0 = 0, but the equation is still fulfilled.
For the second example, k 0 because 0 k 4 | k-4 | = | k| + 4 -(k-4) = k + 4 -k+4 = k + 4 2k = 0 k=0
However, we figured k > 0
Consequently, k cannot exist in the range 0 k 4.
In the third scenario, K >= 4 | k-4 | = | k| + 4 k-4 = k+ 4
However, it is stated in the question that k is an integer. Therefore, it won't be in the area 0 x 1. k must thus be smaller than -1.
K 0, as we can see. As a result, this assertion provides a complete response to the question.
We get 8 = 0
K can't thus be bigger than 4.
We finally get to k 0. Consequently, this claim is adequate to elicit the response.
K > k3 refers to the second claim.
It should be noticed that on the number line, the value of x > x3 only occurs when x -1 or 0 x 1.
Correct Answer: D
Approach Solution 3:
k is considered to be a positive integer. The question is whether k > 0 or not.
We must evaluate whether the two claims are sufficient to solve the issue.
Regarding the first claim, 1)|k-4| = |k| + 4
To get rid of the mod, we must split up the k values into several regions.
We will split the k values when the mod values become 0.
k = 4 and |k-4| = 0.
|k| = 0\sk = 0
In order to do this, we'll split the data into three zones.
K >= 4, K 0, and K 0.
As a result, k = 0
The equation above gives the following results: | k-4 | = | k| + 4 -(k-4) = - k + 4 - k + 4 = -k + 4.
Since we get to 0 = 0, we cannot determine the value of k, but the equation is still true.
In the second instance, k 0 is obtained because 0 k 4 | k-4 | = | k| + 4 -(k-4) = k + 4 -k+4 = k + 4 2k = 0 k=0.
But we concluded that k > 0.
Therefore, k cannot occur in the interval 0 k 4.
K >= 4 | k-4 | = | k| + 4 k-4 = k+ 4 in the third case.
However, the question clearly says that k is an integer. As a result, it won't be in the region 0 x 1. K 0, as we can see, means that k must be less than -1. As a consequence, this claim offers a comprehensive answer to the query.
Since we obtain 8 = 0, K cannot be more than 4.
Finally, we reach k 0. As a result, this argument can generate the desired response.
K > k3 alludes to the second statement.
On the number line, it should be noted that the value of x > x3 only appears when x -1 or 0 x 1.
Correct Answer: D
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