
byRituparna Nath Content Writer at Study Abroad Exams
Question: A rectangular box has dimensions 12*10*8 inches. What is the largest possible value of right cylinder that can be placed inside the box?
- 180\(\pi\)
- 200\(\pi\)
- 300\(\pi\)
- 320\(\pi\)
- 450\(\pi\)
‘A rectangular box has dimensions 12*10*8 inches’ - is the topic from the GMAT Quantitative problem set. To solve GMAT Problem Solving questions a student must have knowledge about a good number of qualitative skills. The GMAT Quant section consists of 31 questions in total. The GMAT quant topics in the problem-solving part require calculative mathematical problems that should be solved with proper mathematical knowledge.
Approach Solution 1:
Dimensions of the box are 12*10*8 inches if radius of a cylinder is 6 then its diameter is 12 and it won't fit on any face of a box. For example it can not fit on 12*10 face of the box since diameter=12>10=side.
Complete solution:
A rectangular box has dimensions 12*10*8 inches. What is the largest possible value of right cylcinder that can be placed inside the box?
\(Volume_{cylinder}\)=\(\pi\)\(r^2\)h
If the cylinder is placed on 8*10 face then it's maximum radius is 8/2=4
Volume
= \(\pi\)*\(4^2\)*12
=192\(\pi\)
If the cylinder is placed on 8*12 face then it's maximum radius is 8/2=4
Volume
= \(\pi\)*\(4^2\)*10
=160\(\pi\)
If the cylinder is placed on 10*12 face then it's maximum radius is 10/2=5
Volume
= \(\pi\)*\(5^2\)*8
=200\(\pi\)
So, the maximum volume is for 200\(\pi\).
Hence, B is the correct answer.
Correct Answer: B
Approach Solution 2:
Candidates must Remember that the base of the cylinder is a circle
r is constant around the circle, so the base can completely fit in a square, not a rectangle. Therefore, they will not be able to use the entire space in the base of
the rectangular box.
the volume of a cylinder is pi * r^2 * h
We must select largest possible r such that the dimensions of the rectangular base allow maximum value or r
We would want to maximize r more than h because r is squared here
so, select bases 10 and 12 allowing a maximum value of r = 5
volume of cylinder: 25 pi * 8 = 200 pi
to check, think if 8 is one of the dimensions of the base, r = 4
volume of cyclinder: 16 pi * (either 10 or 12 ) = 160 pi or 192 pi
not maximum volume
Hence, B is the correct answer.
Correct Answer: B
Approach Solution 3:
this problem can be solved using formula directly. This is a easy and time saving method.
The volume of cylinder is pi * r^2 * h
So, the largest value if r or h are two of the largest value used.
Considering r = 12, h = 10,
we get, v = pi*36*10 = 360pi
And Considering r = 10, h = 12,
we get, v = pi*25*12 = 300pi.
Considering the value of r = 5, h=8
volume of cylinder: 25 pi * 8 = 200 pi
Correct Answer: B
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