A Rectangular Box has Dimensions 12*10*8 Inches GMAT Problem Solving

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Question: A rectangular box has dimensions 12*10*8 inches. What is the largest possible value of right cylinder that can be placed inside the box?

  1. 180\(\pi\)
  2. 200\(\pi\)
  3. 300\(\pi\)
  4. 320\(\pi\)
  5. 450\(\pi\)

‘A rectangular box has dimensions 12*10*8 inches’ - is the topic from the GMAT Quantitative problem set. To solve GMAT Problem Solving questions a student must have knowledge about a good number of qualitative skills. The GMAT Quant section consists of 31 questions in total. The GMAT quant topics in the problem-solving part require calculative mathematical problems that should be solved with proper mathematical knowledge.

Approach Solution 1:
Dimensions of the box are 12*10*8 inches if radius of a cylinder is 6 then its diameter is 12 and it won't fit on any face of a box. For example it can not fit on 12*10 face of the box since diameter=12>10=side.
Complete solution:
A rectangular box has dimensions 12*10*8 inches. What is the largest possible value of right cylcinder that can be placed inside the box?
\(Volume_{cylinder}\)=\(\pi\)\(r^2\)h
If the cylinder is placed on 8*10 face then it's maximum radius is 8/2=4
Volume
= \(\pi\)*\(4^2\)*12
=192\(\pi\)
If the cylinder is placed on 8*12 face then it's maximum radius is 8/2=4
Volume
= \(\pi\)*\(4^2\)*10
=160\(\pi\)
If the cylinder is placed on 10*12 face then it's maximum radius is 10/2=5
Volume
= \(\pi\)*\(5^2\)*8
=200\(\pi\)
So, the maximum volume is for 200\(\pi\).
Hence, B is the correct answer.

Correct Answer: B

Approach Solution 2:

Candidates must Remember that the base of the cylinder is a circle
r is constant around the circle, so the base can completely fit in a square, not a rectangle. Therefore, they will not be able to use the entire space in the base of
the rectangular box.
the volume of a cylinder is pi * r^2 * h
We must select largest possible r such that the dimensions of the rectangular base allow maximum value or r
We would want to maximize r more than h because r is squared here
so, select bases 10 and 12 allowing a maximum value of r = 5
volume of cylinder: 25 pi * 8 = 200 pi
to check, think if 8 is one of the dimensions of the base, r = 4
volume of cyclinder: 16 pi * (either 10 or 12 ) = 160 pi or 192 pi
not maximum volume
Hence, B is the correct answer.

Correct Answer: B

Approach Solution 3:

this problem can be solved using formula directly. This is a easy and time saving method.

The volume of cylinder is pi * r^2 * h
So, the largest value if r or h are two of the largest value used.
Considering r = 12, h = 10,

we get, v = pi*36*10 = 360pi
And Considering r = 10, h = 12,

we get, v = pi*25*12 = 300pi.

Considering the value of r = 5, h=8
volume of cylinder: 25 pi * 8 = 200 pi
Correct Answer: B

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