A Chord of a Circle is Equal to its Radius.

Question: A chord of a circle is equal to its radius. Find the angle subtended by this chord at a point on the major arc.

  1. 45
  2. 22.5
  3. 15
  4. 20
  5. 30

“A Chord of a Circle is Equal to its Radius.”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book "GMAT Official Guide Quantitative Review".  To solve GMAT Problem Solving questions a student must have knowledge about a good number of qualitative skills. GMAT Quant section consists of 31 questions in total. The GMAT quant topics in the problem-solving part require calculative mathematical problems that should be solved with proper mathematical knowledge.

Solution and Explanation:

Approach Solution 1:

It is given in the question that a chord of a circle is equal to its radius. It is asked to find the angle subtended by this chord at a point on the major arc.

Firstly we should note that
The length of the chord equals the radius of the circle.

If we draw two lines from the center of the circle to either end of the chords, we get two more radii, forming an equilateral triangle with the chord.

Therefore, the angle subtended by the chord (or the minor arc created by the chord) at the center is 60 degrees.

We can remember that all three sides of an equilateral triangle are 60 degrees.
So, the angle subtended by the chord on any point on the major arc is 30 degrees.

The correct answer is option E.

Approach Solution 2:

Let us draw a circle with any radius and center O.
Let AO and BO be the 2 radius of the circle
Let AB be the chord equal to the length of the radius.

Now, we will join them to form a triangle.

chord

Here OA = OB = AB
Hence ∆ABO becomes an equilateral triangle.
Draw 2 points C and D on the circle such that they lie on the major arc and minor arc, respectively.
Since ∆ABO is an equilateral triangle, we get ∠AOB = 60°.
For the arc AB, ∠AOB = 2∠ACB as we know that the angle subtended by an arc at the center is double the angle subtended by it at any point on the remaining part of the circle.
∠ACB = 1/2 ∠AOB = 1/2 × 60 = 30°

Hence, E is the correct answer.

Approach Solution 3:

Chord of the Circle = Radius of the Circle
So AOB is an equilateral triangle where, OA=OB=AB
∠AOB = 60°
Now, if 2 angles are made on the same chord, angle at centre is twice the angle at circumference.
∠AOB = 2*∠ACB
60° = 2*∠ACB
∠ACB = 30°

Hence, E is the correct answer.

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