100 Students Appeared for Two Examinations. 60 Passed the First GMAT Problem Solving

Sayantani Barman logo

bySayantani Barman Experta en el extranjero

Question: 100 students appeared for two examinations. 60 passed the first, 50 passed the second and 30 passed both. Find the probability that a student selected at random has failed in both the examinations?

  1. \(\frac{1}{5}\)
  2. \(\frac{1}{7}\)
  3. \(\frac{5}{7}\)
  4. \(\frac{5}{6}\)
  5. \(\frac{6}{7}\)

“100 students appeared for two examinations. 60 passed the first, 50 passed the second and 30 passed both. Find the probability that a student selected at random has failed in both the examinations?”- is a topic of the GMAT Quantitative reasoning section of GMAT. This question has been taken from the book “GMAT Official Guide Quantitative Review”. To solve GMAT Problem Solving questions a student must have knowledge about a good amount of qualitative skills. The GMAT Quant topic in the problem-solving part requires calculative mathematical problems that should be solved with proper mathematical knowledge.

Solution and Explanation

Approach Solution (1):

Let’s calculate the number of the students failed in each of the two exams.

A- 40, B- 50. Now, the next thing to figure out is if these two events are dependent or independent events. These two events are independent events as the outcome of one does not influence the outcome of other. In this ase the following formula hold true.

P (A and B) = P (A) * P (B)

P (A) = \(\frac{2}{5}*\frac{1}{2}=\frac{1}{5}\)

Correct Answer: A

Approach Solution (2):

We can solve this problem by applying the set theory.

Let A = PPL who passed in \(1^{st}\) test = 60
Let C = PPL who passed in \(2^{nd}\) test = 50
Let B = overlap i.e., PPL who passed in both = 30

Then A + B = 60
Therefore A = 30
B + C = 50

Therefore C = 20
A + B + C = 80

Remaining = 20 (PPL who did not pass at all)
\(\frac{200}{100}=\frac{1}{5}\)

Correct Answer: A

Suggested GMAT Problem Solving Questions

Fees Structure

CategoryState
General15556

In case of any inaccuracy, Notify Us! 

Comments


No Comments To Show