Question:

At a certain temperature in a 5 L vessel, 2 moles of carbon monoxide and 3 moles of chlorine were allowed to reach equilibrium according to the reaction,$CO + Cl_{2} <=> COCl_2 $ At equilibrium, if one mole of CO is present then equilibrium constant $(K_c)$ for the reaction is :

Updated On: Aug 19, 2022
  • 2
  • 2.5
  • 3
  • 4
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

We have Equilibrium constant can be calculated as $K_{ c }=\frac{\left[ COCl _{2}\right]}{[ CO ]\left[ Cl _{2}\right]}$ $K_{ c }=\frac{(1 mol / 5 L )}{(1 mol / 5 L ) \times(2 mol / 5 L )}=2.5$
Was this answer helpful?
0
0

Concepts Used:

AC Voltage

When voltage changes its direction after every half cycle is known as alternating voltage. The current flows in the circuit at that time are known as alternating current. The alternating current(AC) follows the sine function which changes its polarity concerning time. Most of the electrical devices are operating on the ac voltage.


Formulas Used:

Basic formula

$P = - \frac{xx^T}{x^Tx}$The a+ b3 formula can be verified, by multiplying (a + b) (a2 - ab + b2) and see whether you get a3 + b3. The a+ b3 formula or the difference of cubes formula is explained below:

a+ b3 Formula = a+ b= (a + b) (a2 - ab + b2)

You can remember these signs using the following trick.

 

Let us learn the a+ b3 formula with a few solved examples.

Proof of a^3+ b^3 Formula

Let us see the verification of a cube plus b cube formula here. To prove or verify that a+ b= (a + b) (a2 - ab + b2) we need to prove here LHS = RHS. Lets begin with the following steps.
LHS = a+ b3
On Solving RHS side we get,
= (a + b) (a2 - ab + b2)
On multiplying the a and b separately with (a2 - ab + b2) we get
= a (a2 - ab + b2) + b(a2 - ab + b2)
= a3 - a2b + ab2 + a2b - ab+ b3
= a3 - a2b + a2b + ab2- ab+ b3
= a3 - 0 + 0 + b3
= a3 + b3
Hence proved, LHS = RHS