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The \($pH$\) of a solution is \($5.0$\). If \($H ^{+}$\)ion concentration is decreased \($100$\) times. Then the solution will be be :
List-I (Equations) | List-II (Types of process) | ||
---|---|---|---|
A. | $K_p > Q $ | 1. | Non-spontaneous |
B. | $\Delta G^{\circ} < RT \, In \, Q $ | 2 | Equilibrium |
C. | $K_p = Q $ | 3 | Spontaneous and endothermic |
D. | $T > \frac{\Delta H}{\Delta S}$ | 4 | Spontaneous |
This is new question created.
Write a balanced equation for the reaction of molecular nitrogen (N2) and oxygen (O2) to form dinitrogen pentoxide. \((f(x)=x^2)\)
When voltage changes its direction after every half cycle is known as alternating voltage. The current flows in the circuit at that time are known as alternating current. The alternating current(AC) follows the sine function which changes its polarity concerning time. Most of the electrical devices are operating on the ac voltage.
$P = - \frac{xx^T}{x^Tx}$Acid is any hydrogen-containing substance that is capable of donating a proton (hydrogen ion) to another substance. Base is an ion or molecule capable of accepting a hydrogen ion from acid.
Physical Properties | ACIDS | BASES |
Taste | Sour | Bitter |
Colour on Litmus paper | Turns blue litmus red | Turns red litmus blue |
Ions produced on dissociation | H+ | OH- |
pH | <7 (less than 7) | >7 (more than 7) |
Strong acids | HCl, HNO3, H2SO4 | NaOH, KOH |
Weak Acids | CH3COOH, H3PO4, H2CO3 | NH4OH |
Type of Reaction | Acid | Bases |
Reaction with Metals | Acid + Metal → Salt + Hydrogen gas (H2) E.g., Zn(s)+ dil. H2SO4 → ZnSO4 (Zinc Sulphate) + H2 | Base + Metal → Salt + Hydrogen gas (H2) E.g., 2NaOH +Zn → Na2ZnO2 (Sodium zincate) + H2 |
Reaction with hydrogen carbonates (bicarbonate) and carbonates | Metal carbonate/Metal hydrogen carbonate + Acid → Salt + Carbon dioxide + Water E.g., HCl+NaOH → NaCl+ H2O 2. Na2CO3+ 2 HCl(aq) →2NaCl(aq)+ H2O(l) + CO2(g) 3. Na2CO3+ 2H2SO4(aq) →2Na2SO4(aq)+ H2O(l) + CO2(g) 4. NaHCO3+ HCl → NaCl+ H2O+ CO2 | Base+ Carbonate/ bicarbonate → No reaction |
Neutralisation Reaction | Base + Acid → Salt + Water E.g., NaOH(aq) + HCl(aq) → NaCl(aq) + H2O(l) | Base + Acid → Salt + Water E.g., CaO+ HCl (l) → CaCl2 (aq)+ H2O (l) |
Reaction with Oxides | Metal oxide + Acid → Salt + Water E.g., CaO+ HCl (l) → CaCl2 (aq)+ H2O (l) | Non- Metallic oxide + Base → Salt + Water E.g., Ca(OH)2+ CO2 → CaCO3+ H2O |
Dissolution in Water | Acid gives H+ ions in water. E.g., HCl → H+ + Cl- HCl + H2O → H3O+ + Cl– | Base gives OH- ions in water. |
Read more on Acids, Bases and Salts
$P = - \frac{xx^T}{x^Tx}$The a3 + b3 formula can be verified, by multiplying (a + b) (a2 - ab + b2) and see whether you get a3 + b3. The a3 + b3 formula or the difference of cubes formula is explained below:
a3 + b3 Formula = a3 + b3 = (a + b) (a2 - ab + b2)
You can remember these signs using the following trick.
Let us learn the a3 + b3 formula with a few solved examples.
Let us see the verification of a cube plus b cube formula here. To prove or verify that a3 + b3 = (a + b) (a2 - ab + b2) we need to prove here LHS = RHS. Lets begin with the following steps.
LHS = a3 + b3
On Solving RHS side we get,
= (a + b) (a2 - ab + b2)
On multiplying the a and b separately with (a2 - ab + b2) we get
= a (a2 - ab + b2) + b(a2 - ab + b2)
= a3 - a2b + ab2 + a2b - ab2 + b3
= a3 - a2b + a2b + ab2- ab2 + b3
= a3 - 0 + 0 + b3
= a3 + b3
Hence proved, LHS = RHS