Question

The force of interaction between two charges $q_{1}=6\, \mu C$ and $q_{2}=2\, \mu C$ is $12\, N$. If charge $q=-2\, \mu C$ is added to each of the charges, then the new force of interaction is

• A. $ 2\times 10^{-7}N $
• B. Zero
• C. $30 \,N$
• D. $ 2\times 10^{-3}N $

Answer 1

The Correct Option is B

New force $F=\frac{1}{4 \pi \varepsilon_{0}} \frac{(6-2)(2-2)}{r^{2}} \times 10^{-12}$ $=0$