How many marks in the JEE Advanced should I have to get into IIT Bhubaneswar for electronics?

The average cutoff required to get admitted for IIT Bhubaneswar for electronics in the JEE advanced was 1991-5690 for the academic year of 2019. However, the minimum marks required for getting into IIT Bhubaneswar for Electronics can’t be determined, as the cutoff ranks vary every year depending on the difficulty level of the paper, different caste, and gender. The papers for JEE advanced in 2016 were tough as compared to that of 2017. As a result, in 2016 the cutoff was lower than what it was in 2017. In 2017, since the paper was easy hence the candidates needed higher marks to achieve the cutoff.

With the level of difficulty of the exam, the cutoff marks for JEE advanced will be changing for the respective years but mostly it stays closer to the previous year’s cutoff. So the previous year’s cutoff rank is the best parameter to calculate your chances for admission.