Which one of the following is the true covalent oxide of iodine?
Updated On: Jul 15, 2022
$I _{2} O _{4}$
$I _{2} O _{5}$
$I _{2} O _{7}$
$I _{2} O _{9}$
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The Correct Option isA
Solution and Explanation
In general, higher the oxidation state, more is the covalent character of the oxide. $I _{2} O _{7}$ and $I _{2} O _{9}$ do not exist. $I _{2} O _{4}$ is ionic in nature. It is infact iodyl iodate $[ IO ]^{+}\left[ IO _{3}\right]^{-}$. The only covalent oxide of iodine is $I _{2} O _{5}$.