Question

$H_2O$ is polar, whereas $BeF_2$ is not because

• A. electronegativity of F is greater than that of O
• B. $H_2O$ involves H-bonding, whereas $BeF_2$ is not a discrete molecule
• C. $H_2O$ involves H-bonding, whereas $BeF_2$ is a discrete molecule
• D. $H_2O$ is linear and $BeF_2$ is angular.

Answer 1

The Correct Option is D

Because of linear shape, dipole moments cancel each other in BeF (F $\overline{ ? }$ Be $\overline{\mapsto}$ F) and thus, it is non-polar, whereas HO is V-shaped and hence, it is polar.