What is the cutoff for IIIT Bhubaneswar?

The cutoff is the minimum score or rank required to be eligible for admission to a particular course or program in a college or university. It varies every year and is influenced by several factors such as the number of applicants, the difficulty level of the entrance examination, and the availability of seats.

For the year 2022, the cutoff for IIIT Bhubaneswar's Computer Science (CS) program was 196 in the fourth round. This means that candidates who scored below 196 were not eligible for admission to the CS program in IIIT Bhubaneswar. Similarly, the cutoff for the Electronics and Communication Engineering (ECE) program was 186 in the fourth round. Candidates who scored below 186 were not eligible for admission to the ECE program in IIIT Bhubaneswar.

It is important to note that the cutoff varies for each round of the admission process. In the first round, the cutoff may be higher as there are more seats available, and as the rounds progress, the cutoff may decrease. Additionally, the cutoff can also vary for different categories of candidates such as General, OBC, SC, ST, and PwD.

It is recommended that candidates check the official website of IIIT Bhubaneswar or contact the admissions office for the latest and most accurate information on the cutoffs for their programs. Candidates should also prepare well for the entrance examinations and aim to score higher than the cutoff to increase their chances of securing admission to IIIT Bhubaneswar.