AIIMS MBBS 2019 Question Paper with Answer Key PDF (May 26 - Afternoon Session)

AIIMS MBBS Questions

• 1.

  Elemental silicon to be used as a semiconductor is purified by

  • heating under vacuum
  • floatation
  • zone refining
  • electrolysis
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• 2.

  1g of water, of volume 1 cm$^3$ at 100?C, is converted into steam at same temperature under normal atmospheric pressure ($\simeq$ ) $1\times 10^5$Pa . The volume of steam formed equals 1671 cm$^3$. If the specific latent heat of vaporisation of water is 2256 J/g, the change in internal energy is,

  • 2423 J
  • 2089 J
  • 167 J
  • 2256 J
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• 3.

  A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction $\frac{1}{\pi}\big(\frac{Wb}{m^2}\big)$ in such a way that its axis makes an angle of 60$^{\circ}$ with $\overrightarrow{B}$ . The magnetic flux linked with the disc is

  • 0.08 Wb
  • 0.01 Wb
  • 0.02 Wb
  • 0.06 Wb
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• 4.

  If N is the number of turns in a coil, the value of self inductance varies as

  • $N^0$
  • N
  • $N^2$
  • $N^{-2}$
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• 5.

  The following equilibria are given : $N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}\, K _{1}$ $N2 + O2 \rightleftharpoons 2NO\, K_2$ $H_2 + \frac{1}{2} O_2 \rightleftharpoons H_2 O \, K_3$ The equilibrium constant of the reaction $2NH_3 + \frac{5}{2} O_2 \rightleftharpoons 2NO + 3H_2 O$ in terms of $K_1,\, K_2$ and $K_3$ is

  • $K_1 K_1 K_3$
  • $\frac{K_1 K_2}{K_3}$
  • $\frac{K_1 K_3^2}{K_2}$
  • $\frac{K_2 K_3^3}{K_1}$
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• 6.

  The neutralization of \(NaOH\) by \(H _{2} SO _{4}\) takes place as follows \(H _{2} SO _{4}+2 NaOH \longrightarrow Na _{2} SO _{4}+ H _{2} O\) 

  For complete neutralization Equivalents of acid = equivalents of base Equivalents of \(NaOH =\) moles \(\times\) acidity \(=1 \times 1=1\) Equivalents of \(H _{2} SO _{4}=\frac{x}{98} \times 2=\frac{x}{49}\) (Mol. mass of \(H _{2} SO _{4}=98\) ) Putting the values \(1 \times 1 =\frac{x}{49}\) \(\Rightarrow x =49\, g\) but \(H _{2} SO _{4}\) is \(70 \%\) let \(y g 70 \% H _{2} SO _{4}\) is required \(\frac{70}{100} \times y =49\) \(\Rightarrow y =70\, g\)

  • 10 min
  • 12 min
  • 20 min
  • 15 min
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