AIIMS MBBS 2019 Question Paper with Answer Key PDF (May 26 - Afternoon Session)

AIIMS MBBS 2019 Question paper with answer key pdf conducted on May 26, 2019 in Afternoon Session is available for download. The exam was successfully organized by AIIMS Delhi. The question paper comprised a total of 200 questions.

AIIMS MBBS 2019 Question Paper with Answer Key PDF Afternoon Session

AIIMS MBBS 2019 Question Paper PDF AIIMS MBBS 2019 Answer Key PDF
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AIIMS MBBS Questions

  • 1.
    The following equilibria are given : $N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}\, K _{1}$ $N2 + O2 \rightleftharpoons 2NO\, K_2$ $H_2 + \frac{1}{2} O_2 \rightleftharpoons H_2 O \, K_3$ The equilibrium constant of the reaction $2NH_3 + \frac{5}{2} O_2 \rightleftharpoons 2NO + 3H_2 O$ in terms of $K_1,\, K_2$ and $K_3$ is

      • $K_1 K_1 K_3$
      • $\frac{K_1 K_2}{K_3}$
      • $\frac{K_1 K_3^2}{K_2}$
      • $\frac{K_2 K_3^3}{K_1}$

    • 2.
      In a potentiometer circuit a cell of EMF $1.5\, V$ gives balance point at $36\, cm$ length of wire. If another cell of EMF $2.5\, V$ replaces the first cell, then at what length of the wire, the balance point occurs ?

        • 60 cm
        • 21.6 cm
        • 64 cm
        • 62 cm

      • 3.
        A circular disc of radius 0.2 meter is placed in a uniform magnetic field of induction $\frac{1}{\pi}\big(\frac{Wb}{m^2}\big)$ in such a way that its axis makes an angle of 60$^{\circ}$ with $\overrightarrow{B}$ . The magnetic flux linked with the disc is

          • 0.08 Wb
          • 0.01 Wb
          • 0.02 Wb
          • 0.06 Wb

        • 4.

          The neutralization of \(NaOH\) by \(H _{2} SO _{4}\) takes place as follows \(H _{2} SO _{4}+2 NaOH \longrightarrow Na _{2} SO _{4}+ H _{2} O\) 

          For complete neutralization Equivalents of acid = equivalents of base Equivalents of \(NaOH =\) moles \(\times\) acidity \(=1 \times 1=1\) Equivalents of \(H _{2} SO _{4}=\frac{x}{98} \times 2=\frac{x}{49}\) (Mol. mass of \(H _{2} SO _{4}=98\) ) Putting the values \(1 \times 1 =\frac{x}{49}\) \(\Rightarrow x =49\, g\) but \(H _{2} SO _{4}\) is \(70 \%\) let \(y g 70 \% H _{2} SO _{4}\) is required \(\frac{70}{100} \times y =49\) \(\Rightarrow y =70\, g\)

            • 10 min
            • 12 min
            • 20 min
            • 15 min

          • 5.
            A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4 \times 10^{-3}$ Wb. The self-inductance of the solenoid is

              • 1.0 henry
              • 4.0 henry
              • 2.5 henry
              • 2.0 henry

            • 6.
              All vertebrates are chordates but all chordates are not vertebrates, why ?

                • Notochord is replaced by vertebral column in adult of some chordates
                • Ventral hollow nerve cord remains throughout life in some chordates
                • All chordates possess vertebral column
                • All chordates possess notochord throughout their life

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