AIIMS MBBS 2019 Question Paper with Answer Key PDF (May 25 - Forenoon Session)

AIIMS MBBS Questions

• 1.

  In a u-tube as shown in figure, water and oil are in the left side and right side of the tube respectively. The heights from the bottom for water and oil columns are 15 cm and 20 cm respectively. The density of the oil is :- [take $\rho_{water}$ = 1000 kg/m$^3$]

  • 1200 kg/m$^3$
  • 750 kg/m$^3$
  • 1000 kg/m$^3$
  • 1333 kg/m$^3$
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• 2.

  Elemental silicon to be used as a semiconductor is purified by

  • heating under vacuum
  • floatation
  • zone refining
  • electrolysis
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• 3.

  The neutralization of \(NaOH\) by \(H _{2} SO _{4}\) takes place as follows \(H _{2} SO _{4}+2 NaOH \longrightarrow Na _{2} SO _{4}+ H _{2} O\) 

  For complete neutralization Equivalents of acid = equivalents of base Equivalents of \(NaOH =\) moles \(\times\) acidity \(=1 \times 1=1\) Equivalents of \(H _{2} SO _{4}=\frac{x}{98} \times 2=\frac{x}{49}\) (Mol. mass of \(H _{2} SO _{4}=98\) ) Putting the values \(1 \times 1 =\frac{x}{49}\) \(\Rightarrow x =49\, g\) but \(H _{2} SO _{4}\) is \(70 \%\) let \(y g 70 \% H _{2} SO _{4}\) is required \(\frac{70}{100} \times y =49\) \(\Rightarrow y =70\, g\)

  • 10 min
  • 12 min
  • 20 min
  • 15 min
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• 4.

  1g of water, of volume 1 cm$^3$ at 100?C, is converted into steam at same temperature under normal atmospheric pressure ($\simeq$ ) $1\times 10^5$Pa . The volume of steam formed equals 1671 cm$^3$. If the specific latent heat of vaporisation of water is 2256 J/g, the change in internal energy is,

  • 2423 J
  • 2089 J
  • 167 J
  • 2256 J
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• 5.

  A long solenoid has 500 turns. When a current of 2 ampere is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4 \times 10^{-3}$ Wb. The self-inductance of the solenoid is

  • 1.0 henry
  • 4.0 henry
  • 2.5 henry
  • 2.0 henry
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• 6.

  The following equilibria are given : $N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}\, K _{1}$ $N2 + O2 \rightleftharpoons 2NO\, K_2$ $H_2 + \frac{1}{2} O_2 \rightleftharpoons H_2 O \, K_3$ The equilibrium constant of the reaction $2NH_3 + \frac{5}{2} O_2 \rightleftharpoons 2NO + 3H_2 O$ in terms of $K_1,\, K_2$ and $K_3$ is

  • $K_1 K_1 K_3$
  • $\frac{K_1 K_2}{K_3}$
  • $\frac{K_1 K_3^2}{K_2}$
  • $\frac{K_2 K_3^3}{K_1}$
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